document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=98379>Question 98379</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Bethany invested $2500, part at 8% per year and the rest at 12% interest per year. In one year, the parts earned equal amounts of interest. determine how much was invested at each rate. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #71530 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=71530\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Bethany invested $2500, part at 8% per year and the rest at 12% interest per year. In one year, the parts earned equal amounts of interest. determine how much was invested at each rate.<BR>\n" );
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document.write( "Let amount invested at 8% be \"x\" ; interest on this is 0.08x dollars<BR>\n" );
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document.write( "Amt left to invest is \"2500-x\"; interest on this is 0.12(2500-x) dollars<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "1st interest = 2nd interest<BR>\n" );
document.write( "0.08x = 0.12(2500-x)<BR>\n" );
document.write( "8x = 12(2500-x)<BR>\n" );
document.write( "8x = 30000-12x<BR>\n" );
document.write( "20x =30000<BR>\n" );
document.write( "x = 1500 dollars (amount invested at 8%)<BR>\n" );
document.write( "2500-x = 1000 dollars ( amount invested at 12%)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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