document.write( "Question 1100749: Find all roots of \"k\" such that 2x^2-kx+2=0 has one real root \n" ); document.write( "
Algebra.Com's Answer #715292 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "\"2x%5E2-kx%2B2\"\"%22%22=%22%22\"\"0\"\r\n" );
document.write( "\r\n" );
document.write( "The discriminant, which is b2-4ac, must be zero in \r\n" );
document.write( "order for this equation to have just one real root:\r\n" );
document.write( "\r\n" );
document.write( "\"discriminant\"\"%22%22=%22%22\"\"b%5E2-4ac\"\"%22%22=%22%22\"\"%28-k%29%5E2-4%282%292%29\"\"%22%22=%22%22\"\"k%5E2-16\"\r\n" );
document.write( "\r\n" );
document.write( "So we set this discriminant equal to zero:\r\n" );
document.write( "\r\n" );
document.write( "\"k%5E2-16\"\"%22%22=%22%22\"\"0\"\r\n" );
document.write( "\r\n" );
document.write( "Solve that either of two ways:\r\n" );
document.write( "\r\n" );
document.write( "First way:\r\n" );
document.write( "\r\n" );
document.write( "\"k%5E2-16\"\"%22%22=%22%22\"\"0\"\r\n" );
document.write( "\r\n" );
document.write( "Add 16 to both sides:\r\n" );
document.write( "\r\n" );
document.write( "\"k%5E2\"\"%22%22=%22%22\"\"16\"\r\n" );
document.write( "\r\n" );
document.write( "Use the principle of square roots:\r\n" );
document.write( "\r\n" );
document.write( "\"k\"\"%22%22=%22%22\"\"%22%22+%2B-+4\"   <-- the answers \r\n" );
document.write( "\r\n" );
document.write( "Second way:\r\n" );
document.write( "\r\n" );
document.write( "\"k%5E2-16\"\"%22%22=%22%22\"\"0\"\r\n" );
document.write( "\r\n" );
document.write( "Factor the left side as the difference of two squares:\r\n" );
document.write( "\r\n" );
document.write( "\"%28k-4%29%28k%2B4%29\"\"%22%22=%22%22\"\"0\"\r\n" );
document.write( "\r\n" );
document.write( "k-4 = 0;  k+4 = 0\r\n" );
document.write( "  k = 4;    k = -4   <-- the answers\r\n" );
document.write( "\r\n" );
document.write( "-------\r\n" );
document.write( "\r\n" );
document.write( "To prove that \"2x%5E2-kx%2B2\"\"%22%22=%22%22\"\"0\" just has one\r\n" );
document.write( "real root when k = 4 or k = -4, we substitute in\r\n" );
document.write( "\r\n" );
document.write( "\"2x%5E2-kx%2B2\"\"%22%22=%22%22\"\"0\"\r\n" );
document.write( "\r\n" );
document.write( "Substituting 4 for k:\r\n" );
document.write( "\r\n" );
document.write( "\"2x%5E2-4x%2B2\"\"%22%22=%22%22\"\"0\"\r\n" );
document.write( "\r\n" );
document.write( "Divide both sides by 2\r\n" );
document.write( "\r\n" );
document.write( "\"x%5E2-2x%2B1\"\"%22%22=%22%22\"\"0\"\r\n" );
document.write( "\r\n" );
document.write( "Factor:\r\n" );
document.write( "\r\n" );
document.write( "\"%28x-1%29%28x-1%29\"\"%22%22=%22%22\"\"0\"\r\n" );
document.write( "\r\n" );
document.write( "x-1 = 0; x-1 = 0\r\n" );
document.write( "  x = 1   x = 1   <-- just 1 root, 1\r\n" );
document.write( "\r\n" );
document.write( "---\r\n" );
document.write( "\r\n" );
document.write( "\"2x%5E2-kx%2B2\"\"%22%22=%22%22\"\"0\"\r\n" );
document.write( "\r\n" );
document.write( "Substituting -4 for k:\r\n" );
document.write( "\r\n" );
document.write( "\"2x%5E2-%28-4%29x%2B2\"\"%22%22=%22%22\"\"0\"\r\n" );
document.write( "\r\n" );
document.write( "\"2x%5E2%2B4x%2B2\"\"%22%22=%22%22\"\"0\"\r\n" );
document.write( "\r\n" );
document.write( "Divide both sides by 2\r\n" );
document.write( "\r\n" );
document.write( "\"x%5E2%2B2x%2B1\"\"%22%22=%22%22\"\"0\"\r\n" );
document.write( "\r\n" );
document.write( "Factor:\r\n" );
document.write( "\r\n" );
document.write( "\"%28x%2B1%29%28x%2B1%29\"\"%22%22=%22%22\"\"0\"\r\n" );
document.write( "\r\n" );
document.write( "x+1 = 0;  x+1 = 0\r\n" );
document.write( "  x = -1    x = -1   <-- just 1 root, -1\r\n" );
document.write( "\r\n" );
document.write( "Edwin

\n" ); document.write( "
\n" ); document.write( "
\n" );