document.write( "Question 1100256: find the compound interest at 5 percent per annum for 3 years on the principal which gives simple interest of Rs. 2400 at the same rate and for the same time. \n" ); document.write( "
Algebra.Com's Answer #715287 by Theo(13342)\"\" \"About 
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simple interest of 5% per year for 3 years would be equal to 2400.\r
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\n" ); document.write( "\n" ); document.write( "formula for simple interest is i = p * r * n.\r
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\n" ); document.write( "\n" ); document.write( "i is the interest
\n" ); document.write( "p is the principal
\n" ); document.write( "r is the interest rate per time period
\n" ); document.write( "n is the number of time periods\r
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\n" ); document.write( "\n" ); document.write( "formula becomes 2400 = p * .05 * 3\r
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\n" ); document.write( "\n" ); document.write( "solve for p to get p = 2400 / (.05 * 3) = 16000\r
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\n" ); document.write( "\n" ); document.write( "i = p * r * n becomes i = 16000 * .05 * 3 which becomes i = 2400\r
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\n" ); document.write( "\n" ); document.write( "you now know that the principal is 16000.\r
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\n" ); document.write( "\n" ); document.write( "the compound interest formula is f = p * (1 + r) ^ n\r
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\n" ); document.write( "\n" ); document.write( "f is the future value
\n" ); document.write( "p is the present value
\n" ); document.write( "r is the interest rate per time period
\n" ); document.write( "n is the number of time periods.\r
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\n" ); document.write( "\n" ); document.write( "in your problem, this becomes:\r
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\n" ); document.write( "\n" ); document.write( "f = 16000 * (1 + .05) ^ 3\r
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\n" ); document.write( "\n" ); document.write( "solve for f to get f = 18522\r
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\n" ); document.write( "\n" ); document.write( "the interest earned is equal to f - p which is equal to 18522 - 16000 which is equal to 2522.\r
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