document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1100726>Question 1100726</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Question for my stat practice exam I cannot figure this out<BR>\n" );
document.write( "Determine the value of z* such that satisfies the conditions below. (Round your answers to two decimal places.)<BR>\n" );
document.write( "(a) &#8722;z* and z* separate the middle 96.6% of all z values from the most extreme 3.4% <BR>\n" );
document.write( "z* =  <BR>\n" );
document.write( "I got 2.12 I do not know if that is correct or not.<BR>\n" );
document.write( " <BR>\n" );
document.write( "(b) &#8722;z* and z* separate the middle 90% of all z values from the most extreme 10% <BR>\n" );
document.write( "(c) &#8722;z* and z* separate the middle 97.8% of all z values from the most extreme 2.2% <BR>\n" );
document.write( "(d) &#8722;z* and z* separate the middle 92% of all z values from the most extreme 8%  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #715283 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=715283\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if the area in the middle is .966, then the area on the outside is 1 - .966 = .034.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "this area is split between the right sige of the area in the middle and thel eft side of the area in the middle.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "therefore you are looking for a z-score that has an area of .017 to the right of it and a z-score that has an area of .017 to the left of it.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "since most tables only tell you that area to the leftof the z-score, then you are looking for the z-score with an area of.017 to the left of it and a z-score with an area of 1 - .017 = .983 to the left of it.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "the z-score with an area of .017 to the left of it is -.212\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "the z-score with an area of .983 to the left of it is 2.12\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "looks like you got it right.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "the area will be between z-scores of -2.12 and 2.12\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "here's a picture of that that looks like.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" src = \"http://theo.x10hosting.com/2017/110901.jpg\" alt=\"$$$\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "follow the same procedure for the others and you should be ok.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "1 minus area in between equals area outside.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "half of the area outside is on the left and half of the area is on the right.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "your problem c would be solved as:\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "area in between is .978.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "area outside is equal to 1 - .978 = .022\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "half of .022 = .011\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "area outside on the left = .011 and area outside on the right = .011.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "you would look for z-score with an area to the left of it = .011\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "that z-score would be equal to -2.29\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "since the normal distribution table is symmetric about the mean, than the z-score with an area of .011 to the right of it should be 2.29.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "check the table for a z-score with an area of .011 to the right of it.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "you do this by finding the z-score with an area of 1 - .011 = .989 to the left of it.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "the z-score table tells you that the score with an area of .989 to the left of it is equal to 2.29\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "here's a picture.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" src = \"http://theo.x10hosting.com/2017/110902.jpg\" alt=\"$$$\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );