document.write( "Question 1100724: What is the nth term for the sequence 3,12,27,48,75....
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #715251 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! See # Question 1100724 Answer by MathLover1\r \n" ); document.write( "\n" ); document.write( "take the differences between the numbers to get: \n" ); document.write( "9, 15, 21, 27\r \n" ); document.write( "\n" ); document.write( "take the second differences by taking the differences of the numbers above: \n" ); document.write( "6, 6, 6\r \n" ); document.write( "\n" ); document.write( "all the second differences are equal to six, which means the equation is quadratic: y=ax^2+bx+c\r \n" ); document.write( "\n" ); document.write( "we can find the a, b, & c values by pluggin in the points (1,3), (2,12), & (3,27) and solving for a,b,& c by elimination:\r \n" ); document.write( "\n" ); document.write( "1a+1b+1c=3 \n" ); document.write( "4a+2b+1c=12 \n" ); document.write( "9a+3b+1c=27\r \n" ); document.write( "\n" ); document.write( "1a+1b+1c=3 \n" ); document.write( "3a+1b+0c=9 \n" ); document.write( "8a+2b+0c=24\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1a+1b+1c=3 \n" ); document.write( "3a+1b+0c=9 \n" ); document.write( "2a+0b+0c=6\r \n" ); document.write( "\n" ); document.write( "2a=6 \n" ); document.write( "a=3\r \n" ); document.write( "\n" ); document.write( "3a+b=9 \n" ); document.write( "b=0\r \n" ); document.write( "\n" ); document.write( "a+b+c=3 \n" ); document.write( "c=0\r \n" ); document.write( "\n" ); document.write( "final equation of nth term is: \n" ); document.write( "\n" ); document.write( " |