document.write( "Question 1100724: What is the nth term for the sequence 3,12,27,48,75....
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Algebra.Com's Answer #715251 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
See # Question 1100724 Answer by MathLover1\r
\n" ); document.write( "\n" ); document.write( "take the differences between the numbers to get:
\n" ); document.write( "9, 15, 21, 27\r
\n" ); document.write( "\n" ); document.write( "take the second differences by taking the differences of the numbers above:
\n" ); document.write( "6, 6, 6\r
\n" ); document.write( "\n" ); document.write( "all the second differences are equal to six, which means the equation is quadratic: y=ax^2+bx+c\r
\n" ); document.write( "\n" ); document.write( "we can find the a, b, & c values by pluggin in the points (1,3), (2,12), & (3,27) and solving for a,b,& c by elimination:\r
\n" ); document.write( "\n" ); document.write( "1a+1b+1c=3
\n" ); document.write( "4a+2b+1c=12
\n" ); document.write( "9a+3b+1c=27\r
\n" ); document.write( "\n" ); document.write( "1a+1b+1c=3
\n" ); document.write( "3a+1b+0c=9
\n" ); document.write( "8a+2b+0c=24\r
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\n" ); document.write( "\n" ); document.write( "1a+1b+1c=3
\n" ); document.write( "3a+1b+0c=9
\n" ); document.write( "2a+0b+0c=6\r
\n" ); document.write( "\n" ); document.write( "2a=6
\n" ); document.write( "a=3\r
\n" ); document.write( "\n" ); document.write( "3a+b=9
\n" ); document.write( "b=0\r
\n" ); document.write( "\n" ); document.write( "a+b+c=3
\n" ); document.write( "c=0\r
\n" ); document.write( "\n" ); document.write( "final equation of nth term is: \"3n%5E2%2B0n%2B0+=+3n%5E2\" or\r
\n" ); document.write( "\n" ); document.write( "\"+3n%5E2\"
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