document.write( "Question 98347: state the domain of the following:\r
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document.write( "m(x) = 5 / (x^2 + 9)\r
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document.write( "I know that the domain will be all x where the denominator does not equal zero, but when I set the denominator to zero, I get stuck:\r
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document.write( "x^2 + 9 = 0
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document.write( "x^2 = -9
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document.write( "x = sqr root -9 ----> you can't take the squareroot of a negative number, so I'm stuck. \r
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document.write( "Please help. \n" );
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Algebra.Com's Answer #71523 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! You are stuck because x^2+9 cannot be zero in the Real \n" ); document.write( "Number System. \n" ); document.write( "--------------- \n" ); document.write( "Graph y=x^2+9 and you will see it is always above the x-axis. \n" ); document.write( "-------------- \n" ); document.write( "Or consider: \n" ); document.write( "If x is Real, x^2 is always greater than or equal to zero; \n" ); document.write( "so if you add 9 the result is always greater that or \n" ); document.write( "equal to 9. \n" ); document.write( "=============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |