document.write( "Question 1100704: What is the probability of not rolling a sum of 10 with two fair​ dice? \n" ); document.write( "
Algebra.Com's Answer #715229 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "I'm assuming each die has 6 sides (labeled 1 through 6). \r
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\n" ); document.write( "\n" ); document.write( "Let's make one die be red and the other be blue.\r
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\n" ); document.write( "\n" ); document.write( "Make a table of all the possible sums that we can make (sums are in black ink)\r
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\n" ); document.write( "\n" ); document.write( "There are 6*6 = 36 sums in the table. Of which, there are 3 copies of 10 (formed by 4+6=10,5+5=10,6+4=10). So that makes 36-3 = 33 copies that are not a sum of 10. \r
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\n" ); document.write( "\n" ); document.write( "Divide the number of copies that aren't ten (33) over the total number of sums (36) to get \"33%2F36+=+11%2F12\". Don't forget to reduce as much as possible.\r
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\n" ); document.write( "\n" ); document.write( "The answer as a fraction is \"11%2F12\"\r
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\n" ); document.write( "\n" ); document.write( "If you need the answer in decimal form, then use a calculator to get this approximate result \"11%2F12=0.9167\" (rounded to 4 decimal places)
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