document.write( "Question 98155: how do you graph using intercept\r
\n" ); document.write( "\n" ); document.write( "4x-3y=12 \n" ); document.write( "

Algebra.Com's Answer #71521 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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How do you graph using intercept
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\n" ); document.write( "4x - 3y = 12
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\n" ); document.write( "Put the graph in the slope intercept form:
\n" ); document.write( "4x - 3y = 12
\n" ); document.write( "-3y = -4x + 12
\n" ); document.write( "We want y to be positive, multiply equation by -1
\n" ); document.write( "3y = +4x - 12
\n" ); document.write( "Divide equation by 3 to get 1y
\n" ); document.write( "y = (4/3)x - (12/3)
\n" ); document.write( "y = (4/3)x - 4, is the slope/intercept form
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\n" ); document.write( "Graph by making a table assigning a value to x and solving for y:
\n" ); document.write( " x | y
\n" ); document.write( "--------
\n" ); document.write( "-3 |-8
\n" ); document.write( " 0 |-4
\n" ); document.write( "+3 | 0
\n" ); document.write( "+6 |
\n" ); document.write( "+9 |
\n" ); document.write( "You should be able to finish this table
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\n" ); document.write( "This is a linear equation so you really only need to have two points, a 3rd
\n" ); document.write( "point, will confirm it as a straight line. should look like this
\n" ); document.write( " $\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+%284%2F3%29x+-+4%29+\"$ \n" ); document.write( "

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