document.write( "Question 1100416: Alan sets off from Campsite A on a bearing of 100 degrees at an average speed of 5.6 kilometres per hour.
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document.write( "At the same time Bob sets off from campsite B on a bearing of 70 degrees.
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document.write( "After 3 hours they both arrive at campsite C.
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document.write( "Who has the faster average speed and by how much? \n" );
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Algebra.Com's Answer #715102 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Alan sets off from Campsite A on a bearing of 100 degrees at an average speed of 5.6 kilometres per hour. \n" ); document.write( " At the same time Bob sets off from campsite B on a bearing of 70 degrees. \n" ); document.write( " After 3 hours they both arrive at campsite C. \n" ); document.write( " Who has the faster average speed and by how much? \n" ); document.write( ": \n" ); document.write( "let s = Bob's speed to C \n" ); document.write( "then \n" ); document.write( "3s = the dist from B to C \n" ); document.write( ": \n" ); document.write( "Draw this out to form a triangle A B C, where \n" ); document.write( "A = 180-100 = 80 degrees \n" ); document.write( "B = 70 degrees \n" ); document.write( "C = 180 - 80 - 70 = 30 degrees \n" ); document.write( ": \n" ); document.write( "Alan's dist (AC): 3 * 5.6 = 16.8 km, (opposite angle B: \n" ); document.write( "Use the law of sines \n" ); document.write( " \n" ); document.write( "I got \n" ); document.write( "3s = \n" ); document.write( "3s = 17.606 \n" ); document.write( "s = 17.606/3 \n" ); document.write( "s = 5.87 km/hr, about .3 km/hr faster \n" ); document.write( " |