document.write( "Question 1100519: Find the open intervals where the function is concave up and concave down.
\n" ); document.write( "f(x)= x^3 -3x^2 -1\r
\n" ); document.write( "\n" ); document.write( "can you also explain the inflection point and how it is related to the concavity since i dont really understand the whole concept\r
\n" ); document.write( "\n" ); document.write( "Thanks for helping out. \n" ); document.write( "
Algebra.Com's Answer #715037 by Boreal(15235)\"\" \"About 
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Graph it
\n" ); document.write( "\"graph%28300%2C300%2C-10%2C10%2C-10%2C10%2Cx%5E3-3x%5E2-1%29\"
\n" ); document.write( "Set first derivative equal to 0
\n" ); document.write( "3x^2-6x=0
\n" ); document.write( "x(2x-6)=0
\n" ); document.write( "x=0, 3 critical points.
\n" ); document.write( "Second derivative is 6x-6=0, x=1.
\n" ); document.write( "At x=1, function is negative, so this is a local maximum
\n" ); document.write( "At x=3, function is positive, so this is a local minimum
\n" ); document.write( "Inflection point is at x=1, where the curve is changing from forming a concave up/down to a concave down/up
\n" ); document.write( "The function is concave down from (-oo, 1) and concave up from (1,+oo)\r
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