document.write( "Question 1100521: The length of a rectangle is
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document.write( "2
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document.write( "ft
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document.write( " longer than its width.
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document.write( "If the perimeter of the rectangle is
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document.write( "36
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document.write( "ft
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document.write( ", find its area. \n" );
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Algebra.Com's Answer #715033 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Width=x \n" ); document.write( "length=x+2 \n" ); document.write( "perimeter=2(width)+2(length)=36 \n" ); document.write( "2x+2x+4=36 \n" ); document.write( "4x+4=36 \n" ); document.write( "4x=32 \n" ); document.write( "x=8 feet width \n" ); document.write( "x+2=10 feet length. \n" ); document.write( "Area is length*width=80 ft^2. \n" ); document.write( " |