document.write( "Question 1100496: the Allison are on a cross-country trip with the Jensons. One day they get separated and the Jensons are 20 miles ahead of the Allosons on the road. if the Jensons average 50mph and the Allisons travel 60mph. how long will it be before the Alissons catch up with the Jensons/ \n" ); document.write( "
Algebra.Com's Answer #715031 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Rate x Time = Distance
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "So for the Jensons,
\n" ); document.write( "\"D%5BJ%5D=50%2AT%2B20\" since they're already 20 miles ahead.
\n" ); document.write( "and for the Allisons,
\n" ); document.write( "\"D%5BA%5D=60%2AT\"
\n" ); document.write( "So find \"T\" when,
\n" ); document.write( "\"D%5BJ%5D=D%5BA%5D\"
\n" ); document.write( "\"50T%2B20=60T\"
\n" ); document.write( "\"10T=20\"
\n" ); document.write( "Solve for \"T\" in hours.
\n" ); document.write( "
\n" ); document.write( "
\n" );