document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1100448>Question 1100448</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Bianca has nine major assignments to complete for school this week.Two of them involve writing essays. Bianca decides to work on three of the nine assignments tonight. What is the probability that one of the assignment is an essay ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #714952 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=714952\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2 of Bianca's assignments are essays, meaning 7 of them are not. So, the probability of all 3 being non-essays would be (7/9)^3, or 0.47050754458161865569272976680384. Therefore, the probability of at least 1 being as essay is 1-0.47050754458161865569272976680384, or 0.53<BR>\n" );
document.write( "&#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );