document.write( "Question 1100461: How am i to get the solution to the equation |x-3|=2x+1?
\n" ); document.write( "It says I am to end up with a extraneous solution, but I do not know what that means or how to get it.
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Algebra.Com's Answer #714946 by KMST(5328)\"\" \"About 
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Maybe \"x-3%3E=0\" , and then \"abs%28x-3%29=x-3\" ,
\n" ); document.write( "or maybe \"x-3%3C0\" and then \"abs%28x-3%29=-%28x-3%29\" .
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\n" ); document.write( "If \"x-3%3C0\" ,
\n" ); document.write( "the equation simplifies to
\n" ); document.write( "\"-%28x-3%29=2x%2B1\" <--> \"-x%2B3=2x%2B1\" <--> \"3-1=2x%2Bx\" <--> \"2=3x\" <--> \"x=2%2F3\" .
\n" ); document.write( "That is a solution of \"-%28x-3%29=2x%2B1\" ,
\n" ); document.write( "but is it a solution of the original equation?
\n" ); document.write( "Let's check.
\n" ); document.write( "If \"x=2%2F3\" , \"x-3=2%2F3-3=-7%2F3\" and \"abs%28x-3%29=7%2F3\" .
\n" ); document.write( "At the same time, if \"x=2%2F3\" , \"2x%2B1=2%2A%282%2F3%29%2B1=4%2F3%2B1=7%2F3\" .
\n" ); document.write( "Clearly, \"x=2%2F3\" makes \"abs%28x-3%29=2x%2B1\" true,
\n" ); document.write( "so \"highlight%28x=2%2F3%29\" is a solution of \"abs%28x-3%29=2x%2B1\" .
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\n" ); document.write( "What about the case when \"x-3%3E=0\" ?
\n" ); document.write( "Will that lead to another solution?
\n" ); document.write( "If \"x-3%3E=0\" ,
\n" ); document.write( "the equation simplifies to
\n" ); document.write( "\"x-3=2x%2B1\" <--> \"-3-1=2x-x\" <--> \"-4=x\" .
\n" ); document.write( "\"x=-4\" is a solution to \"x-3=2x%2B1\" ,
\n" ); document.write( "but it is not a solution to the original equation.
\n" ); document.write( "It makes \"x-3=-7\" , \"abs%28x-3%29=7\" , and
\n" ); document.write( "\"2x%2B1=2%2A%28-4%29%2B1=-8%2B1=-7\" .
\n" ); document.write( "Clearly, if \"x=-4\" makes \"abs%28x-3%29=7\" , and \"2x%2B1=-7\" ,
\n" ); document.write( "it is not a solution to \"abs%28x-3%29=2x%2B1\" .
\n" ); document.write( "we call it an extraneous solution.
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