document.write( "Question 1100461: How am i to get the solution to the equation |x-3|=2x+1?
\n" ); document.write( "It says I am to end up with a extraneous solution, but I do not know what that means or how to get it. \n" ); document.write( "
Algebra.Com's Answer #714942 by Alan3354(69443)\"\" \"About 
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How am i to get the solution to the equation |x-3|=2x+1?
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\n" ); document.write( "x-3 = 2x+1
\n" ); document.write( "x = 2x + 4
\n" ); document.write( "-x = 4
\n" ); document.write( "x = -4
\n" ); document.write( "Check:
\n" ); document.write( "|-4-3| = -7
\n" ); document.write( "|-7| = -7
\n" ); document.write( "NG
\n" ); document.write( "Absolute value cannot be negative.
\n" ); document.write( "--> extraneous solution
\n" ); document.write( "===============
\n" ); document.write( "-(x-3) = 2x+1
\n" ); document.write( "-x+3 = 2x+1
\n" ); document.write( "3 = 3x+1
\n" ); document.write( "3x = 2
\n" ); document.write( "x = 2/3
\n" ); document.write( "=================
\n" ); document.write( "Check:
\n" ); document.write( "|x-3|=2x+1
\n" ); document.write( "|(2/3 - 3)| = 4/3+1 = 7/3
\n" ); document.write( "|-7/3| = 7/3
\n" ); document.write( "No problem.
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