document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=98316>Question 98316</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve 6(n+1 power)&#8805; 10. Round to four decimal places. This is Greek to me. I'm trying to help my niece and I have no clue where to start. Your assistance will be greatly appreciated. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #71493 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=71493\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> taking the log gives (n+1)(log6)>=(log10) ... n+1>=log10/log6 ... n>=(log10/log6)-1 ... n>=0.2851 </SPAN>\n" );
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