document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1100432>Question 1100432</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An astronaut on the moon throws a baseball upward. The height of the ball in feet (y) is related to the number of seconds since the ball was thrown (x). <BR>\n" );
document.write( "y=-2.7x^2+30x+6.5<BR>\n" );
document.write( "A. How high will the ball be after 3 seconds? <BR>\n" );
document.write( "B. Give two approximate times (in seconds) that the ball will be at a height of 75 feet.  <BR>\n" );
document.write( " How many seconds on its way up?<BR>\n" );
document.write( "C. How many seconds on its way down?<BR>\n" );
document.write( "Please help me solve this! Im stuck, thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #714923 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=714923\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -2.7x^2+30x+6.5=y<BR>\n" );
document.write( "at 3 seconds<BR>\n" );
document.write( "-9(2.7)+90+6.5=72.2 feet.<BR>\n" );
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document.write( "-2.7x^2+30x+6.5=75<BR>\n" );
document.write( "-2.7x^2+30x-68.5=0 <BR>\n" );
document.write( "since approximate is desired, graph it.  <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28300%2C300%2C-3%2C12%2C-10%2C100%2C-2.7x%5E2%2B30x%2B6.5%2C75%29 ALIGN=MIDDLE  ALT=\"graph%28300%2C300%2C-3%2C12%2C-10%2C100%2C-2.7x%5E2%2B30x%2B6.5%2C75%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "3 and 8 seconds. We know 3 seconds is approximate from the first, and f(8)=73.7.<BR>\n" );
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document.write( "on the way up need the vertex, which has a t value of -b/2a, and that is -30/-5.4 or 5.6 seconds.  Same time down. </SPAN>\n" );
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