document.write( "Question 1100433: A sum of money is divided between George, Tony, and John in the ratio 3:2:1. However, George dies and it is decided to divide his share between Tony and John in the ratio 1:3. If after George’s share is divided John has $100 more than Tony, how much money was there altogether?\r
\n" ); document.write( "\n" ); document.write( "If you could help to solve this problem that would be great!\r
\n" ); document.write( "\n" ); document.write( "tried
\n" ); document.write( "3:2:1
\n" ); document.write( " x(1/3+1/2+1/1)=1
\n" ); document.write( "

Algebra.Com's Answer #714917 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
In the beginning, it was \"S=3x%2B2x%2Bx=6x\".
\n" ); document.write( "So then George's share is split up into fourths.
\n" ); document.write( "One forth to Tony, three fourths to John.
\n" ); document.write( "So then Tony has,
\n" ); document.write( "\"T=2x%2B%281%2F4%29%283x%29=2x%2B%283%2F4%29x=%2811%2F4%29x\"
\n" ); document.write( "and John has,
\n" ); document.write( "\"J=x%2B%283%2F4%29%283x%29=x%2B%289%2F4%29x=%2813%2F4%29x\"
\n" ); document.write( "and
\n" ); document.write( "\"J=T%2B100\"
\n" ); document.write( "Substituting,
\n" ); document.write( "\"%2813%2F4%29x=%2811%2F4%29x%2B100\"
\n" ); document.write( "\"%282%2F4%29x=100\"
\n" ); document.write( "\"x=200\"
\n" ); document.write( "Originally,
\n" ); document.write( "\"S=6x\"
\n" ); document.write( "\"S=6%28200%29\"
\n" ); document.write( "\"S=1200\"
\n" ); document.write( "
\n" );