document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=97783>Question 97783</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the vertex and focus of the parabola given by:\r<BR>\n" );
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document.write( "               x^2= -1/8 y<BR>\n" );
document.write( "                       </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #71484 by </B><A HREF=/tutors/aboutme.mpl?userid=ryanman><B>ryanman(19)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ryanman><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=71484\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Vertex (0,0) and the directrx is parallel to the x-axis and the parabola opens down since the P is negative .<BR>\n" );
document.write( "4P = -1/8<BR>\n" );
document.write( "P=-1/32\r<BR>\n" );
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document.write( "so the focus is 1/32 units below the vertex (since the parabola opens downwards) , so the focus is at (0,-1/32) </SPAN>\n" );
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