document.write( "Question 98208: square root of 11(square root of 11 + x square root 22) \r
\n" ); document.write( "\n" ); document.write( "How do i do this kind of problem? I am lost it is\r
\n" ); document.write( "\n" ); document.write( "square root of 11 times square root of 11 plus x square root of 22
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Algebra.Com's Answer #71477 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
Given:
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\n" ); document.write( "\"sqrt%2811%29%2A%28sqrt%2811%29+%2B+x%2Asqrt%2822%29%29\"
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\n" ); document.write( "This is a problem involving distributed multiplication. It is of the form:
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\n" ); document.write( "\"A%2A%28B+%2B+C%29+=+A%2AB+%2B+A%2AC\" <=== call this rule 1
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\n" ); document.write( "Notice that you are just multiplying the term outside the parentheses by each of the terms
\n" ); document.write( "inside the parentheses.
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\n" ); document.write( "What makes this problem a little \"different\" is that it involves multiplication of square roots,
\n" ); document.write( "so you need to know a few rules about those multiplications. Here are a couple of rules for
\n" ); document.write( "square roots:
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\n" ); document.write( "\"sqrt%28A%29%2A+sqrt%28A%29+=+A\" <=== call this rule 2
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\n" ); document.write( "and:
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\n" ); document.write( "\"sqrt%28A%2AB%29+=+sqrt%28A%29%2Asqrt%28B%29\" <=== call this rule 3
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\n" ); document.write( "It seems as if this problem involves a lot of \"sqrt%2811%29\" terms. But notice that there
\n" ); document.write( "is one term that is \"sqrt%2822%29\". If we apply rule 3 to that term, we can get a \"sqrt%2811%29\"
\n" ); document.write( "from it by doing the following:
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\n" ); document.write( "\"sqrt%2822%29+=+sqrt%282%2A11%29+=+sqrt%282%29%2Asqrt%2811%29\"
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\n" ); document.write( "So in the problem we can replace \"sqrt%2822%29\" by \"sqrt%282%29%2Asqrt%2811%29\" and the problem
\n" ); document.write( "then becomes:
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\n" ); document.write( "\"sqrt%2811%29%2A%28sqrt%2811%29%2B+x%2Asqrt%282%29%2Asqrt%2811%29%29\"
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\n" ); document.write( "Now let's apply rule 1. We'll do that by multiplying \"sqrt%2811%29\" times each of the
\n" ); document.write( "terms in the parentheses to get:
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\n" ); document.write( "\"sqrt%2811%29%2Asqrt%2811%29+%2B+sqrt%2811%29%2Ax%2Asqrt%282%29%2Asqrt%2811%29\"
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\n" ); document.write( "Now we can apply rule 2 to both of these terms. The first term is \"sqrt%2811%29%2Asqrt%2811%29\"
\n" ); document.write( "and rule 2 tells us that the answer is just 11. So substituting 11 into the problem reduces
\n" ); document.write( "the problem to:
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\n" ); document.write( "\"11+%2B+sqrt%2811%29%2Ax%2Asqrt%282%29%2Asqrt%2811%29\"
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\n" ); document.write( "Notice now that in the second term there is also a \"sqrt%2811%29%2Asqrt%2811%29\" involved. Rule
\n" ); document.write( "2 also allows us to replace that product with 11. And this substitution further reduces the
\n" ); document.write( "problem to:
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\n" ); document.write( "\"11+%2B+11%2Ax%2Asqrt%282%29\"
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\n" ); document.write( "That's the answer to this problem. I suppose that if you wanted to you could factor out
\n" ); document.write( "the 11 that is common to both terms to get \"11%2A%281+%2B+x%2Asqrt%282%29%29\" but that's up to you
\n" ); document.write( "and what your instructions are.
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\n" ); document.write( "Hope this helps you to understand the problem a little more.
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