document.write( "Question 1100281: In​ 2012, the population of a city was 5.72 million. The exponential growth rate was 3.79 per year.
\n" ); document.write( "​a) Find the exponential growth function.
\n" ); document.write( "​b) Estimate the population of the city in 2018.
\n" ); document.write( "​c) When will the population of the city be 88 ​million?
\n" ); document.write( "​d) Find the doubling time.\r
\n" ); document.write( "\n" ); document.write( "This one's also a big one and it is pretty hard.
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Algebra.Com's Answer #714768 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
In​ 2012, the population of a city was 5.72 million. The exponential growth rate was 3.79 per year.
\n" ); document.write( "​a) Find the exponential growth function.
\n" ); document.write( "A(t) = 5.72*3.79^t
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\n" ); document.write( "​b) Estimate the population of the city in 2018.
\n" ); document.write( "A(6) = 5.72*2.79^6
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\n" ); document.write( "​c) When will the population of the city be 88 ​million?
\n" ); document.write( "Solve for \"t\"::
\n" ); document.write( "88 = 5.72*2.79^t
\n" ); document.write( "2.79^t = 15.38
\n" ); document.write( "t = log(15.38)/(log(2.79)) = 2.66 years
\n" ); document.write( "Ans:: 2018 + 2.66 yrs = 2021
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\n" ); document.write( "​d) Find the doubling time.
\n" ); document.write( "2*5.72 = 5.72*3.79^t
\n" ); document.write( "3.79^t = 2
\n" ); document.write( "t = log(2)/log(3.79)
\n" ); document.write( "t = 0.52
\n" ); document.write( "Ans:: 2018 + 0.52(12 mts) = 2018 and 6 mts
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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\n" ); document.write( "This one's also a big one and it is pretty hard.
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