document.write( "Question 1100281: In 2012, the population of a city was 5.72 million. The exponential growth rate was 3.79 per year.
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document.write( "a) Find the exponential growth function.
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document.write( "b) Estimate the population of the city in 2018.
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document.write( "c) When will the population of the city be 88 million?
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document.write( "d) Find the doubling time.\r
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document.write( "This one's also a big one and it is pretty hard. \n" );
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Algebra.Com's Answer #714768 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! In 2012, the population of a city was 5.72 million. The exponential growth rate was 3.79 per year. \n" ); document.write( "a) Find the exponential growth function. \n" ); document.write( "A(t) = 5.72*3.79^t \n" ); document.write( "------------------------------- \n" ); document.write( "b) Estimate the population of the city in 2018. \n" ); document.write( "A(6) = 5.72*2.79^6 \n" ); document.write( "-------------------------------- \n" ); document.write( "c) When will the population of the city be 88 million? \n" ); document.write( "Solve for \"t\":: \n" ); document.write( "88 = 5.72*2.79^t \n" ); document.write( "2.79^t = 15.38 \n" ); document.write( "t = log(15.38)/(log(2.79)) = 2.66 years \n" ); document.write( "Ans:: 2018 + 2.66 yrs = 2021 \n" ); document.write( "--------------------------- \n" ); document.write( "d) Find the doubling time. \n" ); document.write( "2*5.72 = 5.72*3.79^t \n" ); document.write( "3.79^t = 2 \n" ); document.write( "t = log(2)/log(3.79) \n" ); document.write( "t = 0.52 \n" ); document.write( "Ans:: 2018 + 0.52(12 mts) = 2018 and 6 mts \n" ); document.write( "-------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------- \n" ); document.write( "This one's also a big one and it is pretty hard. \n" ); document.write( " \n" ); document.write( " |