document.write( "Question 1100257: Hi
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document.write( "1/2 of the sweets in box a were equal to 3/8 of the sweets in box b.
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document.write( "240 sweets from box b were taken out and box a had 3 times as many sweets as box b.\r
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document.write( "what the total number of sweets in both boxes at first. \r
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document.write( "How many sweets would have to be taken out from box a so that there would be 1/4 as many sweets in box a as in box b.\r
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document.write( "thank s \n" );
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Algebra.Com's Answer #714765 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! a/2=3b/8 \n" ); document.write( "a=3*(b-240)\r \n" ); document.write( "\n" ); document.write( "a/2=3b/8 \n" ); document.write( "3*(b-240)/2=3b/8 \n" ); document.write( "(b-240)/2=b/8 \n" ); document.write( "b-240=b/4 \n" ); document.write( "4*b-4*240=b \n" ); document.write( "3*b=4*240 \n" ); document.write( "b=4*80 \n" ); document.write( "b=320\r \n" ); document.write( "\n" ); document.write( "a=3*(b-240) \n" ); document.write( "a=3*(320-240) \n" ); document.write( "a=3*(80) \n" ); document.write( "a=240 \n" ); document.write( "check \n" ); document.write( "remove 240 from 320 in box b is 80 \n" ); document.write( "box a now has 240 and box b 80 \n" ); document.write( "240 is three times 80\r \n" ); document.write( "\n" ); document.write( "This second question is unclear. After or before the 240 are removed? \n" ); document.write( "How many sweets would have to be taken out from box a so that there would be 1/4 as many sweets in box a as in box b. \n" ); document.write( " \n" ); document.write( " |