document.write( "Question 1100175: Fimd six numbers in AP, such that the sum of the two extremes be 16 and the product of the two middle terms be 63. \n" ); document.write( "
Algebra.Com's Answer #714745 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! If the sum of the first and last numbers is an integer and the product of the two middle terms is an integer, then almost certainly all the numbers will be integers. \n" ); document.write( "Then if the product of the middle two numbers is 63, the two middle numbers are 7 and 9. \n" ); document.write( "So the common difference is 2; that makes the 6 numbers \n" ); document.write( "3, 5, 7, 9, 11, 13 \n" ); document.write( "You could, of course, solve the problem using algebra; however, it takes far more work than the logical analysis solution shown above. \n" ); document.write( "Let the first term be a and the common difference be d; then the 6 numbers are \n" ); document.write( "a, a+d, a+2d, a+3d, a+4d, a+5d \n" ); document.write( "Then \n" ); document.write( "(1) \n" ); document.write( "(2) \n" ); document.write( "Solve equation (1) for a: \n" ); document.write( "Substitute into equation (2): \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Substitute back into equation (1) to find a: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "I think I like the logical analysis solution better.... \n" ); document.write( " \n" ); document.write( " |