document.write( "Question 98319: Simplify: 1+i/2-i\r
\n" ); document.write( "\n" ); document.write( "Hopefully, before the end of the year I will be much better at this. Some of us grandparents aren't as smart as you young people.
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Algebra.Com's Answer #71473 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Simplify: 1+i/2-i
\n" ); document.write( "Hopefully, before the end of the year I will be much better at this. Some of us grandparents aren't as smart as you young people. \r
\n" ); document.write( "\n" ); document.write( "First of all, I'm not exactly sure what the problem is.\r
\n" ); document.write( "\n" ); document.write( "I am assuming that it's:\r
\n" ); document.write( "\n" ); document.write( "\"%281%2Bi%29%2F%282-i%29\"
\n" ); document.write( "and not
\n" ); document.write( "\"1%2B%28i%2F2%29-i\"
\n" ); document.write( "\"%281%2Bi%29%2F%282-i%29\" multiply both numerator and denominator by \"%282%2Bi%29\" the conjugate of \"%282-i%29\". This will get rid of the radical in the denominator:\r
\n" ); document.write( "\n" ); document.write( "\"%28%281%2Bi%29%282%2Bi%29%29%2F%28%282-i%29%282%2Bi%29%29\" Multiply out using the FOIL(first, outer, inner, last) crutch
\n" ); document.write( "\"%282%2Bi%2B2i%2Bi%5E2%29%2F%284%2B2i-2i-i%5E2%29\" combine like terms in numerator and denominator
\n" ); document.write( "(note:\"i%5E2=-1\")
\n" ); document.write( "\"%281%2B3i%29%2F5\"\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
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