document.write( "Question 792848: A boy can swim down stream four times as fast as he swim up stream. If he can swim up stream and down stream in a total of 22 minutes, how many minutes does it takes him to swim upstream \n" ); document.write( "
Algebra.Com's Answer #714714 by amalm06(224)![]() ![]() You can put this solution on YOUR website! Upstream: d=(r)(t1)\r \n" ); document.write( "\n" ); document.write( "Downstream: d=(4r)(t2)\r \n" ); document.write( "\n" ); document.write( "(r)(t1)=(4r)(t2)\r \n" ); document.write( "\n" ); document.write( "t1=(4)(t2)\r \n" ); document.write( "\n" ); document.write( "t2=22-t1\r \n" ); document.write( "\n" ); document.write( "t1=(4)(22-t1)\r \n" ); document.write( "\n" ); document.write( "t1=88-(4)(t1)\r \n" ); document.write( "\n" ); document.write( "(5)(t1)=88\r \n" ); document.write( "\n" ); document.write( "t1=88/5 min (Answer) \n" ); document.write( " |