document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=384440>Question 384440</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Swimming downstream, a swimmer can cover 0.5 mile in 6 minutes. It takes the swimmer 30 minutes to swim back up the stream. Find the speed of the swimmer in still water and the speed of the current. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #714711 by </B><A HREF=/tutors/aboutme.mpl?userid=amalm06><B>amalm06(224)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amalm06><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amalm06><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=714711\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Downstream: d=rt-->(v+c)(6)=0.5-->v+c=0.08333<BR>\n" );
document.write( "Upstream: d=rt-->(v-c)(30)=0.5-->v-c=0.01666\r<BR>\n" );
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document.write( "v=c+0.01666--> 0.01666+2c=0.08333-->2c=0.06667-->c=0.0333 mi/min= 2 mi/hr\r<BR>\n" );
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document.write( "v=0.05003 mi/hr=3 mi/hr\r<BR>\n" );
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document.write( "Speed of swimmer in still water: 3 mi/hr (Answer)<BR>\n" );
document.write( "Speed of current: 2 mi/hr (Answer) \r<BR>\n" );
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