document.write( "Question 1100189: please help me solve this equation \"+log+base10%28x%2B9%29=1%2Blog+base10%28x%2B1%29-log+base10%28x-2%29+\" \n" ); document.write( "
Algebra.Com's Answer #714685 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
\"+log+base10%28x%2B9%29=1%2Blog+base10%28x%2B1%29-log+base10%28x-2%29+\"
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\n" ); document.write( "base 10 is the default, and does not need to be spec'd
\n" ); document.write( "\"log%28x%2B9%29+=+1%2Blog%28x%2B1%29+-+log%28x-2%29\"
\n" ); document.write( "\"log%28x%2B9%29+=+log%2810%29+%2B+log%28x%2B1%29+-+log%28x-2%29\"
\n" ); document.write( "= \"log%28x%2B9%29+=+log%2810%2A%28x%2B1%29%29+-+log%28x-2%29\"
\n" ); document.write( "= \"log%28x%2B9%29+=+log%2810%2A%28x%2B1%29%2F%28x-2%29%29\"
\n" ); document.write( "x+9 = 10*(x+1)/(x-2)
\n" ); document.write( "Can you do the rest?
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