document.write( "Question 1100180: Janet can do a job in 3 hours while Garry can do the same job in 2 hours. If Janet works for an hour before Garry helps her, how long will it take them to finish the job together? \n" ); document.write( "
Algebra.Com's Answer #714665 by Alan3354(69443)\"\" \"About 
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Janet can do a job in 3 hours while Garry can do the same job in 2 hours. If Janet works for an hour before Garry helps her, how long will it take them to finish the job together?
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\n" ); document.write( "similar problem
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\n" ); document.write( "one house used alone can fill a swimming pool with water in 4 hours another house used alone can fill the same swimming pool in 6 hours of both houses are used together how long will it take to fill the pool
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\n" ); document.write( "I would use hoses, not houses.
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\n" ); document.write( "can fill a swimming pool with water in 4 hours --> 1/4 pool/hour
\n" ); document.write( "fill the same swimming pool in 6 hours --> 1/6 pool/hour
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\n" ); document.write( "1/4 + 1/6 = 5/12 pools/hour
\n" ); document.write( "--> 12/5 = 2.4 hours
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\n" ); document.write( "For parallel flows, parallel work, parallel resistors, use product/sum.
\n" ); document.write( "4*6/(4+6) = 2.4 hours \n" ); document.write( "
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