document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1100167>Question 1100167</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Make R the subject of --------S= D^2/ (D-R)^2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #714658 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=714658\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> start with S = D^2/ (D-R)^2\r<BR>\n" );
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document.write( "multiply both sides of the equation by (D-R)^2 and divide both sides of the equation by S.\r<BR>\n" );
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document.write( "you will get (D-R)^2 = D^2 / S\r<BR>\n" );
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document.write( "take the square root of both sides of the equation.\r<BR>\n" );
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document.write( "you will get D-R = plus or minus sqrt(D^2 / S)\r<BR>\n" );
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document.write( "subtract D from from both sides of the equation.\r<BR>\n" );
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document.write( "you will get -R = -D plus or minus sqrt(D^2 / S)\r<BR>\n" );
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document.write( "multiply both sides of the equation by -1.\r<BR>\n" );
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document.write( "you will get R = D - (plus or minus sqrt(D^2 / S)\r<BR>\n" );
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document.write( "this results in R = D minus or plus sqrt(D^2 / S).\r<BR>\n" );
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document.write( "this is the same as R = D plus or minus sqrt(D^2 / S).\r<BR>\n" );
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document.write( "that's your solution.\r<BR>\n" );
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document.write( "to determine if this solution is accurate, then work your way back and solve for S.\r<BR>\n" );
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document.write( "you will start with either R = D plus sqrt(D^2 / S) or R = D minus sqrt(D^2 / S).\r<BR>\n" );
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document.write( "in both cases, you will be able to get back to the original equation.\r<BR>\n" );
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