document.write( "Question 1100054: Mark, Andrew and Dick shared some money. Mark had 480 dollars more than Andrew. Dick had 3 times as much as Mark. When Dick used 600 dollars, the total amount of money that Dick and Andrew had was 1500 dollars. \r
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Algebra.Com's Answer #714587 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
m=a+480
\n" ); document.write( "d=3*m
\n" ); document.write( "d-600+a=1500
\n" ); document.write( "substitute
\n" ); document.write( "3*m-600+a=1500
\n" ); document.write( "substitute again
\n" ); document.write( "3*(a+480)-600+a=1500
\n" ); document.write( "3*a+3*480-600+a=1500
\n" ); document.write( "3*a+3*480-600+a=1500
\n" ); document.write( "4*a=1500+600-1440
\n" ); document.write( "4*a=660
\n" ); document.write( "a=660/4
\n" ); document.write( "a=165 for Andrew
\n" ); document.write( "m=a+480
\n" ); document.write( "m=165+480=645 for Mark
\n" ); document.write( "d=3*m
\n" ); document.write( "d=3*645=1935 for Dick
\n" ); document.write( "check
\n" ); document.write( "1935-600=1335
\n" ); document.write( "165+1335=1500
\n" ); document.write( "ok\r
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