document.write( "Question 1100010: An investor invested a total of $2,300 in two mutual funds. One fund earned a 6% profit while the other earned a 3% profit. If the investor's total profit was $90, how much was invested in each mutual fund? \n" ); document.write( "

Algebra.Com's Answer #714517 by ikleyn(52944) $\"\"$ $\"About$

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document.write( "0.06*x + 0.03(2300-x) = 90.\r\n" );
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document.write( "6x + 3*(2300-x) = 100*90\r\n" );
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document.write( "6x + 6900 - 3x = 9000\r\n" );
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document.write( "3x = 9000 - 69000 = 2100  ====>  x =  = 700.\r\n" );
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document.write( "Answer.  $700 at 6%  and  $2300 - $700 = $1600 at 3%.\r\n" );
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document.write( "Check.   0.06*700 + 0.03*1600 = 90.   ! Correct !\r\n" );
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\n" ); document.write( "To see more solved problems on investments with detailed solutions/explanations, look into the lesson \r
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