document.write( "Question 1100038: There are some nickels, dimes, and quarters in a large piggy bank.
\n" ); document.write( "For every 2 nickels, there are 3 dimes.
\n" ); document.write( "For every 2 dimes, there are 5 quarters.
\n" ); document.write( "There are 500 coins in all.
\n" ); document.write( "How many nickels, dimes, and quarters are in the piggy bank?
\n" ); document.write( "How much are the coins in the piggy bank worth all together?\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #714513 by ikleyn(52798)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "
\r\n" );
document.write( "n + d + q = 500,   (1)\r\n" );
document.write( "\r\n" );
document.write( "2n = 3d            (2)      (\"For every 2 nickels, there are 3 dimes.\")\r\n" );
document.write( "\r\n" );
document.write( "2d = 5q            (3)      (\"For every 2 dimes, there are 5 quarters.\")\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "From (2),  n = \"%283%2F2%29%2Ad\".\r\n" );
document.write( "\r\n" );
document.write( "From (3),  q = \"%285%2F2%29%2Ad\".\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Substitute  (4)  and  (5) into (1).  You will get\r\n" );
document.write( "\r\n" );
document.write( "\"3%2F2%29%2Ad\" + d + \"%285%2F2%29%2Ad\" = 500.\r\n" );
document.write( "\r\n" );
document.write( "Multiply by 2 both sides:\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "3d + 2d + 5d = 1000  ===>  10d = 1000  ====>  d = \"1000%2F10\" = 100.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Answer.  100 dimes,  150 nickels  and  250  quarters.\r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "==============
\n" ); document.write( "O-o-o-p-s !\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The other tutor CORRECTLY DETERMINED that the above solution is wrong.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "I agree, it is WRONG !\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So, below I place the corrected solution. Thanks, @richwmiller !
\n" ); document.write( "==============\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\r\n" );
document.write( "n + d + q = 500,   (1)\r\n" );
document.write( "\r\n" );
document.write( "\"n%2F2\" = \"d%2F3\"            (2)      (\"For every 2 nickels, there are 3 dimes.\")\r\n" );
document.write( "\r\n" );
document.write( "\"d%2F2\" = \"q%2F5\"            (3)      (\"For every 2 dimes, there are 5 quarters.\")\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "From (2),  n = \"%282%2F3%29%2Ad\".\r\n" );
document.write( "\r\n" );
document.write( "From (3),  q = \"%285%2F2%29%2Ad\".\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Substitute  (4)  and  (5) into (1).  You will get\r\n" );
document.write( "\r\n" );
document.write( "\"%282%2F3%29%2Ad\" + d + \"%285%2F2%29%2Ad\" = 500.\r\n" );
document.write( "\r\n" );
document.write( "Multiply by 6 both sides:\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "4d + 6d + 15d = 3000  ===>  25d = 3000  ====>  d = \"3000%2F25\" = 120.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Answer.  120 dimes,  \"%282%2F3%29%2A120\" = 80 nickels  and  \"%285%2F2%29%2A120\" = 300 quarters.\r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );