document.write( "Question 98276: Jane invested $24,000, part at 7% and part at 3%. If the total interest at the end of the year is $880, how much did she invest at 7%\r
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document.write( "An employee who produces x units per hour earns an hourly wage of y+0.45x+12(in dollars). Find the hourly wage for an employee who produces 17 units per hour. \n" );
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Algebra.Com's Answer #71446 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! .07*X+.03(24,000-X)=880 \n" ); document.write( ".07X+720-.03X=880 \n" ); document.write( ".04X=880-720 \n" ); document.write( ".04X=160 \n" ); document.write( "X=160/.04 \n" ); document.write( "X=4000 INVESTED @ 7%. \n" ); document.write( "24,000-4,000=20,000 INVESTED @ 3%. \n" ); document.write( "PROOF \n" ); document.write( ".07*4000+.03*20,000=880 \n" ); document.write( "280+600=880 \n" ); document.write( "880=880 \n" ); document.write( " \n" ); document.write( " |