document.write( "Question 1099978: If cos A= -4/5 for angle A in Quadrant II, find tan A/2 I'm doing this on A+LS it's giving me a lot of trouble the answer, how to do it, plus alternate forms would really be appreciated even when I have the right answer sometimes it registers as wrong. \n" ); document.write( "

Algebra.Com's Answer #714459 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"+cos%28+A+%29+=+-4%2F5+\"$
\n" ); document.write( "The angle is in the 2nd quadrant
\n" ); document.write( "cos is negative
\n" ); document.write( "sin is positive
\n" ); document.write( "tan is negative
\n" ); document.write( " $\"+tan%28+A%2F2+%29+=+%28+1-cos%28A%29+%29+%2F+sin%28+A+%29+\"$
\n" ); document.write( " $\"+tan%28+A%2F2+%29+=+%28+1+-%28-4%2F5%29+%29+%2F+%28+3%2F5+%29+\"$
\n" ); document.write( " $\"+tan%28+A%2F2+%29+=+%28+5%2F5+%2B+4%2F5+%29+%2F+%283%2F5%29+\"$
\n" ); document.write( " $\"+tan%28+A%2F2+%29+=+%28+5+%2B+4+%29%2F3+\"$
\n" ); document.write( " $\"+tan%28+A%2F2+%29+=+3+\"$
\n" ); document.write( "( note that $\"+A%2F2+\"$ is in the 1st quadrant )
\n" ); document.write( " \n" ); document.write( "

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