document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1099931>Question 1099931</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 9x^2+39-14 I have to factor using ac method  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #714447 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=714447\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Assume it is:<BR>\n" );
document.write( " 9x^2 + 39x - 14 = 0<BR>\n" );
document.write( "look at the factors of 14, 2 & 7, 1, 14<BR>\n" );
document.write( "(3x + 14)(3x - 1) = 0<BR>\n" );
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document.write( "Check this by FOILing the above, 9x^2 - 3x + 42x - 14<BR>\n" );
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