document.write( "Question 1099950: Janet set off on a bicycle trip at 6:00 am at an average rate of 22 miles per hour. Her husband, Bob, promised to bring her some lunch, and he set off by car 2 hours after Janet left, driving at an average speed of 50 miles per hour. At what time did Bob catch up with Janet? \n" ); document.write( "
Algebra.Com's Answer #714446 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Find Janet's head start in miles
\n" ); document.write( "\"+d%5B1%5D+=+22%2A2+\"
\n" ); document.write( "\"+d%5B1%5D+=+44+\" mi
\n" ); document.write( "---------------------
\n" ); document.write( "Start a stopwatch when Bob leaves at 8:00
\n" ); document.write( "Let \"+t+\" = time in hrs on the stopwatch
\n" ); document.write( "when Bob catches up with Janet
\n" ); document.write( "----------------------------------------
\n" ); document.write( "Let \"+d+\" = distance in miles that Bob travels
\n" ); document.write( "until he catches up with Janet
\n" ); document.write( "-----------------------------------------
\n" ); document.write( "Janet's equation:
\n" ); document.write( "(1) \"+d+-+d%5B1%5D+=+22t+\"
\n" ); document.write( "(1) \"+d+-+44+=+22t+\"
\n" ); document.write( "Bob's equation:
\n" ); document.write( "(2) \"+d+=+50t+\"
\n" ); document.write( "------------------------
\n" ); document.write( "Plug (2) into (1)
\n" ); document.write( "(1) \"+50t+-+44+=+22t+\"
\n" ); document.write( "(1) \"+28t+=+44+\"
\n" ); document.write( "(1) \"+t+=+1.5714+\"
\n" ); document.write( "and
\n" ); document.write( "\"+.5714%2A60+=+34.2857+\"
\n" ); document.write( "\"+.2857%2A60+=+17+\"
\n" ); document.write( "---------------------------
\n" ); document.write( "\"+8+%2B+1+=+9+\"
\n" ); document.write( "Bob catches up at 9:34:17
\n" ); document.write( "---------------------------
\n" ); document.write( "check:
\n" ); document.write( "(1) \"+d+-+44+=+22t+\"
\n" ); document.write( "(1) \"+d+=+22%2A1.5714+%2B+44+\"
\n" ); document.write( "(1) \"+d+=+34.5708+%2B+44+\"
\n" ); document.write( "(1) \"+d+=+78.5708+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+d+=+50t+\"
\n" ); document.write( "(2) \"+d+=+50%2A1.5714+\"
\n" ); document.write( "(2) \"+d+=+78.57+\"
\n" ); document.write( "Close enough
\n" ); document.write( "--------------------------
\n" ); document.write( "Get a 2nd opinion if needed\r
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