document.write( "Question 1099950: Janet set off on a bicycle trip at 6:00 am at an average rate of 22 miles per hour. Her husband, Bob, promised to bring her some lunch, and he set off by car 2 hours after Janet left, driving at an average speed of 50 miles per hour. At what time did Bob catch up with Janet? \n" ); document.write( "
Algebra.Com's Answer #714446 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! Find Janet's head start in miles \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "--------------------- \n" ); document.write( "Start a stopwatch when Bob leaves at 8:00 \n" ); document.write( "Let \n" ); document.write( "when Bob catches up with Janet \n" ); document.write( "---------------------------------------- \n" ); document.write( "Let \n" ); document.write( "until he catches up with Janet \n" ); document.write( "----------------------------------------- \n" ); document.write( "Janet's equation: \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "Bob's equation: \n" ); document.write( "(2) \n" ); document.write( "------------------------ \n" ); document.write( "Plug (2) into (1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "--------------------------- \n" ); document.write( " \n" ); document.write( "Bob catches up at 9:34:17 \n" ); document.write( "--------------------------- \n" ); document.write( "check: \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "and \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "Close enough \n" ); document.write( "-------------------------- \n" ); document.write( "Get a 2nd opinion if needed\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |