document.write( "Question 1099951: what percent of the number should be subtracted to get the original number back if we add 10% of a number itself? \n" ); document.write( "
Algebra.Com's Answer #714444 by josmiceli(19441)\"\" \"About 
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\"+n+%2B+.1n+=+1.1n+\"
\n" ); document.write( "Let \"+x+\" = the percent of \"+1.1n+\"
\n" ); document.write( "to be subtracted to give me \"+n+\"
\n" ); document.write( "\"+1.1n+-+%28+x%2F100+%29%2A1.1n+=+n+\"
\n" ); document.write( "\"+1.1n%2A%28+1+-+x%2F100+%29+=+n+\"
\n" ); document.write( "\"+1.1%2A%28+1+-+x%2F100+%29+=+1+\"
\n" ); document.write( "\"+1+-+x%2F100+=+1%2F1.1+\"
\n" ); document.write( "\"+x%2F100+=+1+-+1%2F1.1+\"
\n" ); document.write( "\"+x%2F100+=+1+-+.90909+\"
\n" ); document.write( "\"+x%2F100+=+.090909+\"
\n" ); document.write( "\"+x+=+9.091+\"
\n" ); document.write( "9.091% of 1.1n must be subtracted to get \"+n+\"
\n" ); document.write( "--------------------
\n" ); document.write( "Get a 2nd opinion if needed
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