document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1099925>Question 1099925</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The salt water content of salt water is 5% (based on its weight). How many pounds of tap water should be mixed with 30 kg of sea water so that the result contains 3% salt. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #714433 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=714433\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The salt water content of salt water is 5% (based on its weight).<BR>\n" );
document.write( " How many pounds of tap water should be mixed with 30 kg of sea water so that the result contains 3% salt.<BR>\n" );
document.write( ":<BR>\n" );
document.write( "let x = amt of water required to accomplish this<BR>\n" );
document.write( "A typical mixture equation, percent in the decimal form<BR>\n" );
document.write( ".05(30) = .03(x+30)<BR>\n" );
document.write( "1.5 = .03x + .9<BR>\n" );
document.write( "1.5 - .9 = .03x<BR>\n" );
document.write( ".6 = .03x<BR>\n" );
document.write( "x = .6/.03<BR>\n" );
document.write( "x = 20 kg of tap water required   </SPAN>\n" );
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