document.write( "Question 1099798: The parents of 5 students are invited to attend their graduation ceremony. They are arranged to be seated in a row of 10 VIP seats. How many ways can they be seated if any 3 pairs of parents are to be seated to their own spouse.\r
\n" ); document.write( "\n" ); document.write( "ANS from tutorial bk : 403200 ( i just need to show steps )
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Algebra.Com's Answer #714393 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "(1) Choose the 3 pairs of parents out of the total of 5 pairs to be the ones that will be seated next to their spouses: C(5,3) = 10 {\"5 choose 3\").
\n" ); document.write( "(2)Treat each of the three pairs as units; then the number of ways of arranging those 3 units and the other 4 single parents is 7! = 5040.
\n" ); document.write( "(3) In each of the 3 pairs, the two spouses can be arranged in either of 2 ways: 2*2*2 = 8.

\n" ); document.write( "All together, the total number of ways of arranging the 10 people is \"10%2A5040%2A8+=+403200\".

\n" ); document.write( "IMPORTANT NOTE:

\n" ); document.write( "I used your given answer to get that result.

\n" ); document.write( "As the problem is written, I think the answer should be different -- because in many of the 7! arrangements of the 3 pairs of parents and the other 4 parents (step (2) above), other pairs of spouses will be seated next to each other. But the problem IMPLIES that EXACTLY 3 pairs of parents are supposed to be seated next to each other.

\n" ); document.write( "Counting the number of ways in that case would be far more complicated....
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