document.write( "Question 1099892: man invests $2500 in two accounts. one account earns 2% and the other account earns 9%.the total profit is $113.How much is invested in the two accounts
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Algebra.Com's Answer #714377 by richwmiller(17219)\"\" \"About 
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Total amount of money invested: $2500
\n" ); document.write( "x+y=2500,
\n" ); document.write( "Total yearly interest for the two accounts is: $113
\n" ); document.write( "0.02*x+0.09*y=113
\n" ); document.write( "x=2500-y
\n" ); document.write( "Substitute for x
\n" ); document.write( "0.02*(2500-y)+0.09*y=113
\n" ); document.write( "Multiply out
\n" ); document.write( "50-0.02*y+0.09*y=113
\n" ); document.write( "Combine like terms.
\n" ); document.write( "0.07*y=63
\n" ); document.write( "Isolate y
\n" ); document.write( "y=$900.00 at 9% earns $81 interest
\n" ); document.write( "x=2500-y
\n" ); document.write( "Calculate x
\n" ); document.write( "x=$1600.00 at 2% earns $32 interest
\n" ); document.write( "Check
\n" ); document.write( "0.02*1600+0.09*900=113
\n" ); document.write( "32+81=113
\n" ); document.write( "113=113
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\n" ); document.write( "\n" ); document.write( " Tutor greenestamps,
\n" ); document.write( "I always enjoy seeing your alternate methods of solution.
\n" ); document.write( "Thanks.
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