document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=98260>Question 98260</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the length of a square whose diagonal is three ft. longer than the side </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #71433 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=71433\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x= length of side<BR>\n" );
document.write( "x+3=lendth of diagonal<BR>\n" );
document.write( "we have a right angle isoscoles triangle.<BR>\n" );
document.write( "a^2+b^2=c^2<BR>\n" );
document.write( "so 2x^2=(x+3)^2<BR>\n" );
document.write( "2x^2=x^2+6x+9<BR>\n" );
document.write( "subtract 2x^2 from each side: -x^2+6x+9=0<BR>\n" );
document.write( "multiply -1 times both sides: x^2-6x-9=0<BR>\n" );
document.write( "Quadratic formula: x=7.24... and x=-1.24...(extraneous)<BR>\n" );
document.write( "the diagonal=10.24...<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "2(7.24...)^2=(10.24...)^2<BR>\n" );
document.write( "104.8=104.9 (.1 rounding error)<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );