document.write( "Question 1099730: Find the equation of the line tangent to the circle x2 + y2 = 25 at point (3,4) \n" ); document.write( "
Algebra.Com's Answer #714264 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "Find the equation of the line tangent to the circle x2 + y2 = 25 at point (3,4)
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Calculus is UNNECESSARY here. How many people who ask questions on here know calculus? Help these people with the SIMPLEST steps so they can understand.\r
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document.write( "Looking at the the equation of the circle, the center is located at the origin, or at coordinate point: (0, 0). With the point of tangency being (3, 4), the slope of the radius line is: \"4%2F3\"
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document.write( "Now, as a tangent and radius line intersect at a perpendicular point, it follows that the tangent line's slope is \"-+3%2F4\".
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document.write( "With the tangent line's point of (3, 4), and a slope of \"-+3%2F4\", we use the point-slope form, or \"matrix%281%2C3%2C+y+-+y%5B1%5D%2C+%22=%22%2C+m%28x+-+x%5B1%5D%29%29\" to find the equation of the tangent line
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document.write( "\"matrix%281%2C3%2C+y+-+4%2C+%22=%22%2C+%28-+3%2F4%29%28x+-+3%29%29\"
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document.write( "\"matrix%281%2C3%2C+y+-+4%2C+%22=%22%2C+%28-+3%2F4%29x+%2B+9%2F4%29\"
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document.write( "\"matrix%281%2C3%2C+y%2C+%22=%22%2C+%28-+3%2F4%29x+%2B+9%2F4+%2B+16%2F4%29\"
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document.write( "\"highlight_green%28matrix%281%2C3%2C+y%2C+%22=%22%2C+%28-+3%2F4%29x+%2B+25%2F4%29%29\" \n" );
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