document.write( "Question 1099766: Can you please put y=3x+6 into a word problem \n" ); document.write( "
Algebra.Com's Answer #714226 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "Let's say that you have 6 movies on your shelf. Each week you add on 3 more movies, so that after x weeks, you have added a total of 3x movies (3x = 3*x = 3 times x). In total, you have 3x+6 movies. If y is the number of movies you have after x weeks, then y = 3x+6\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "If you wanted to figure out how many movies you have say after 3 weeks, then you'd plug in x = 3 to get y = 3*x+6 = 3*3+6 = 9+6 = 15 so you have 15 movies after 3 weeks.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "If you wanted to figure out how many weeks it takes to get a certain number of movies, say 21 movies, then plug y = 21 into the equation and solve for x
\n" ); document.write( "y = 3x+6
\n" ); document.write( "21 = 3x+6
\n" ); document.write( "21-6 = 3x+6-6
\n" ); document.write( "15 = 3x
\n" ); document.write( "3x = 15
\n" ); document.write( "3x/3 = 15/3
\n" ); document.write( "x = 5
\n" ); document.write( "So it takes you 5 weeks to have a total of 21 movies\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );