document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1099699>Question 1099699</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me to solve these two questions-<BR>\n" );
document.write( "1)what principle will amount to rupees 13680 in 1 year and 9 months at 8%p.a.?<BR>\n" );
document.write( "2)what rate gives rupees 900 interest in a sum of rupees 45000 in 73 days? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #714195 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=714195\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=Po(1+.08/1)^1.75<BR>\n" );
document.write( "=13680(1.08^1.75) round at end<BR>\n" );
document.write( "=15,652.3 rupees<BR>\n" );
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document.write( "I=prt<BR>\n" );
document.write( "p=45000, r unknown, t=1/5 of a year, I=900<BR>\n" );
document.write( "900=45000*(1/5)*r<BR>\n" );
document.write( "900=9000r<BR>\n" );
document.write( "r=0.1 or 10% </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );