document.write( "Question 1099735: Write a system of three equations to solve applied problems\r
\n" ); document.write( "\n" ); document.write( "The concentration of dissolved oxygen in water varies with temperature. Between 0∘C−50∘C0∘C−50∘C , the relationship can be modeled as a quadratic function. Use the data in the table below to write a system of equations that, if solved, would help you find the quadratic function.\r
\n" ); document.write( "\n" ); document.write( "T ( ∘C)∘C) Dissolved oxygen (mgL)(mgL)
\n" ); document.write( "10 11.27
\n" ); document.write( "20 9.07
\n" ); document.write( "30 7.54
\n" ); document.write( "

Algebra.Com's Answer #714189 by Alan3354(69443)\"\" \"About 
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10 11.27
\n" ); document.write( "20 9.07
\n" ); document.write( "30 7.54
\n" ); document.write( "----------------
\n" ); document.write( "since it's a quadratic, find the parabola thru the 3 points.
\n" ); document.write( "y = ax^2 + bx + c
\n" ); document.write( "---
\n" ); document.write( "11.27 = 100a + 10b + c
\n" ); document.write( "9.07 = 400a + 20b + c
\n" ); document.write( "7.54 = 900a + 30b + c
\n" ); document.write( "---------
\n" ); document.write( "Eliminate c
\n" ); document.write( "9.070 = 400a + 20b + c
\n" ); document.write( "11.27 = 100a + 10b + c
\n" ); document.write( "--------------------------- Subtract
\n" ); document.write( "-2.2 = 300a + 10b Eqn A
\n" ); document.write( "---
\n" ); document.write( "7.54 = 900a + 30b + c
\n" ); document.write( "9.07 = 400a + 20b + c
\n" ); document.write( "--------------------------- Subtract
\n" ); document.write( "-1.53 = 500a + 10b Eqn B
\n" ); document.write( "10b = -1.53 - 500a
\n" ); document.write( "10b = -2.2 - 300a --- From Eqn A
\n" ); document.write( "-----
\n" ); document.write( "Since both = 10b:
\n" ); document.write( "-1.53 - 500a = -2.2 - 300a
\n" ); document.write( "200a = 0.67
\n" ); document.write( "a = 0.00335
\n" ); document.write( "Sub for a, find b, then find c
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\n" ); document.write( "There's a \"shortcut\" when the x values are evenly spaced, but this always works.\r
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