document.write( "Question 98223: Please check to see if I am doing this the correct way. \r
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document.write( "SOLVE AND CHECK
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document.write( "~(4x+4)+12=0\r
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document.write( "~(4x+4)=-12\r
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document.write( "(~(4x+4))^(2)=(-12)^(2)\r
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document.write( "(~(4(x+1)))^(2)=(-12)^(2)\r
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document.write( "(2)^(2)=(-12)^(2)\r
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document.write( "(2~(x+1))^(2)=(-12)^(2)\r
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document.write( "4(x+1)=(-12)^(2)\r
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document.write( "(4x+4)=(-12)^(2)\r
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document.write( "4x+4=(-12)^(2)\r
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document.write( "4x+4=(144)\r
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document.write( "4x+4=144\r
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document.write( "4x=140\r
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document.write( "x=35\r
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document.write( "No Solution\r
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document.write( "Thank you \n" );
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Algebra.Com's Answer #71418 by benni1013(206)![]() ![]() ![]() You can put this solution on YOUR website! Hold on and back the heck up: Here is how you do this problem. \n" ); document.write( "(4x+4)+12=0 \n" ); document.write( "(4x+4)=-12. You right up to this point now pay attention \n" ); document.write( "4(x+1)=-12. See what I did I made a GCF out the quantity inside the parentheses. \n" ); document.write( "x+1=-3 \n" ); document.write( "x=-4 \n" ); document.write( " |