document.write( "Question 98151: Write qn equation of the line that passes through (9, 6) and is perpendicular to the line whose equation is y=-1/3x+7.\r
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document.write( "So far I have:
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document.write( "y=3x7/3
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document.write( "y-(6)=7/3 (x-9)
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document.write( "y+6=7/3x3\r
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document.write( "This is as far as I can go. I am trying to assist my niece and at the age of 55, my brain is not what it use to be. \n" );
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Algebra.Com's Answer #71415 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Write an equation of the line that passes through (9, 6) and is perpendicular to the line whose equation is y =-(1/3)x + 7. \n" ); document.write( ": \n" ); document.write( "The relationship for the slopes of perpendicular lines is: m1*m2 = -1 \n" ); document.write( "m1 = -1/3, find m2 \n" ); document.write( "(-1/3)*m2 = -1 \n" ); document.write( "multiply by -1 \n" ); document.write( " m2 = +3; it looks like you got that part OK \n" ); document.write( ": \n" ); document.write( "Use the point slope equation: y - y1 = m(x - x1) \n" ); document.write( ": \n" ); document.write( "In this equation: m = +3; x1 = 9; y1 = 6 \n" ); document.write( ": \n" ); document.write( "y - 6 = 3(x - 9) \n" ); document.write( "y - 6 = 3x - 27 \n" ); document.write( "y = 3x - 27 + 6 \n" ); document.write( "y = 3x - 21 is perpendicular to y = -(1/3)x + 7 \n" ); document.write( ": \n" ); document.write( "Check by substituting 9 for x in the above equation \n" ); document.write( "y = 3(9) - 21 \n" ); document.write( "Y = 27 - 21 \n" ); document.write( "Y = 6 \n" ); document.write( ": \n" ); document.write( "Should look like this: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |