document.write( "Question 1099619: A five-card poker hand is dealt from a standard deck of cards. Find the probability that:
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\n" ); document.write( "(“kind” means the face value of the card. e.g. “3” or “Q”)\r
\n" ); document.write( "\n" ); document.write( "c. The hand contains of at least 3 Kings.
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Algebra.Com's Answer #714069 by Edwin McCravy(20056)\"\" \"About 
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A five-card poker hand is dealt from a standard deck of cards.
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document.write( "So the denominator of each probabilities will be: \r\n" );
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document.write( "(52 cards, choose 5) = 52C5 = 2598960\r\n" );
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\n" ); document.write( "Find the probability that:
\n" ); document.write( "a. The hand contains exactly 3 hearts and exactly 2 spades
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document.write( "(13 hearts, choose 3)ื(13 spades, choose 2) = (13C3)ื(13C2) = 22308\r\n" );
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document.write( "Probability = 22308/2598960 = 143/16660\r\n" );
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\n" ); document.write( "b. The hand contains 2 of one kind and 3 of another kind
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document.write( "Probability = 3744/2598960 = 6/4165\r\n" );
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\n" ); document.write( "c. The hand consists of at least 3 Kings.
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document.write( "Case 1:  Hand contains exactly 3 Kings:\r\n" );
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document.write( "(4 Kings, choose 3)ื(48 non-Kings, choose 1) = (4C3)ื(48C1) = 4ื48 = 192\r\n" );
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document.write( "Case 2:  Hand contains all 4 Kings:\r\n" );
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document.write( "(4 Kings, choose 4) = 4C4 = 1\r\n" );
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document.write( "Total for Case 1 and Case 2 = 192+1 = 193\r\n" );
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document.write( "Probability = 193/2598960\r\n" );
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document.write( "Edwin
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