document.write( "Question 1099615: A student plans to spend $200.0 on \"P\"notebooks .but the price of the notebooks had increased by $10.0.As a result,the number of notebooks the student could buy was reduced by 1 .find the price of each notebook before the increase \n" ); document.write( "
Algebra.Com's Answer #714054 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! number of notebooks* cost per notebook=200 \n" ); document.write( "p* cost=200 \n" ); document.write( "cost=200/p \n" ); document.write( "after \n" ); document.write( "number is now p-1* cost is (200/p-1)=200\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(200)/(p-1)-10=(200/p), after cost is 10 more, so subtract 10 to make both the same. \n" ); document.write( "multiply everything by p(p-1) \n" ); document.write( "200p-10p(p-1)=200(p-1) \n" ); document.write( "200p-10p^2+10p=200p-200 \n" ); document.write( "-10p^2+10p+200=0 or \n" ); document.write( "p^2-p-20=0, dividing both sides by -10 \n" ); document.write( "(p-5)(p+4)=0 \n" ); document.write( "p=5 notebooks, with original cost of $40 each. ANSWER \n" ); document.write( "after the price increase, for $200, four notebooks could be bought. \n" ); document.write( " \n" ); document.write( " |