document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1099437>Question 1099437</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many g of gold should a coin of 59% gold be it when combined with a 9 g pure gold necklace  it forms a metal that is 74%  gold? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #713908 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=713908\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let g be the weight of the coin, which is 59% gold. Then:<BR>\n" );
document.write( ".59g + 9=0.74(g+9)<BR>\n" );
document.write( ".59g+9=0.74g+6.66<BR>\n" );
document.write( ".15g=2.34<BR>\n" );
document.write( "g=15.6 gm as the weight of the coin<BR>\n" );
document.write( "&#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );